0=m^2+22m+121

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Solution for 0=m^2+22m+121 equation: 



0=m^2+22m+121

We move all terms to the left:

0-(m^2+22m+121)=0

We add all the numbers together, and all the variables

-(m^2+22m+121)=0

We get rid of parentheses

-m^2-22m-121=0

We add all the numbers together, and all the variables

-1m^2-22m-121=0

a = -1; b = -22; c = -121;
Δ = b2-4ac
Δ = -222-4·(-1)·(-121)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{22}{-2}=-11$

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